Base | Representation |
---|---|
bin | 11110110100111010… |
… | …110110011001101011 |
3 | 10011102210200011011101 |
4 | 132310322312121223 |
5 | 1020242111102011 |
6 | 23112253542231 |
7 | 2251152116623 |
oct | 366472663153 |
9 | 104383604141 |
10 | 33100097131 |
11 | 13046161982 |
12 | 64b91a4977 |
13 | 31767253ba |
14 | 1860069883 |
15 | cdad912c1 |
hex | 7b4eb666b |
33100097131 has 2 divisors, whose sum is σ = 33100097132. Its totient is φ = 33100097130.
The previous prime is 33100097113. The next prime is 33100097153. The reversal of 33100097131 is 13179000133.
Together with previous prime (33100097113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 33100097131 - 27 = 33100097003 is a prime.
It is a super-2 number, since 2×331000971312 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 33100097131.
It is not a weakly prime, because it can be changed into another prime (33100097101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16550048565 + 16550048566.
It is an arithmetic number, because the mean of its divisors is an integer number (16550048566).
Almost surely, 233100097131 is an apocalyptic number.
33100097131 is a deficient number, since it is larger than the sum of its proper divisors (1).
33100097131 is an equidigital number, since it uses as much as digits as its factorization.
33100097131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1701, while the sum is 28.
Adding to 33100097131 its reverse (13179000133), we get a palindrome (46279097264).
The spelling of 33100097131 in words is "thirty-three billion, one hundred million, ninety-seven thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •