Base | Representation |
---|---|
bin | 100101101000010110011111… |
… | …1100001010111000000000000 |
3 | 1121101222102020102122102210002 |
4 | 1023100230333201113000000 |
5 | 321341111140414413100 |
6 | 3131551522554255132 |
7 | 126502025015320262 |
oct | 11320547741270000 |
9 | 1541872212572702 |
10 | 331001310310400 |
11 | 9651595a536024 |
12 | 3115a3311274a8 |
13 | 1129039c4177a2 |
14 | 5ba4798271b32 |
15 | 2840184e292d5 |
hex | 12d0b3f857000 |
331001310310400 has 312 divisors, whose sum is σ = 832981356373344. Its totient is φ = 130436982374400.
The previous prime is 331001310310361. The next prime is 331001310310423. The reversal of 331001310310400 is 4013013100133.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6630477440 + ... + 6630527360.
Almost surely, 2331001310310400 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 331001310310400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (416490678186672).
331001310310400 is an abundant number, since it is smaller than the sum of its proper divisors (501980046062944).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
331001310310400 is an equidigital number, since it uses as much as digits as its factorization.
331001310310400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50915 (or 50888 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 331001310310400 its reverse (4013013100133), we get a palindrome (335014323410533).
The spelling of 331001310310400 in words is "three hundred thirty-one trillion, one billion, three hundred ten million, three hundred ten thousand, four hundred".
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