331001313131 has 2 divisors, whose sum is σ = 331001313132. Its totient is φ = 331001313130.

The previous prime is 331001313101. The next prime is 331001313173. The reversal of 331001313131 is 131313100133.

It is a weak prime.

It is an emirp because it is prime and its reverse (131313100133) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-331001313131 is a prime.

It is a super-4 number, since 4×331001313131⁴ (a number of 47 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (331001313101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165500656565 + 165500656566.

It is an arithmetic number, because the mean of its divisors is an integer number (165500656566).

Almost surely, 2^331001313131 is an apocalyptic number.

331001313131 is a deficient number, since it is larger than the sum of its proper divisors (1).

331001313131 is an equidigital number, since it uses as much as digits as its factorization.

331001313131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 331001313131 its reverse (131313100133), we get a palindrome (462314413264).

The spelling of 331001313131 in words is "three hundred thirty-one billion, one million, three hundred thirteen thousand, one hundred thirty-one".