Base | Representation |
---|---|
bin | 1001101000100011100… |
… | …00001000011110101111 |
3 | 1011122101200022002210022 |
4 | 10310101300020132233 |
5 | 20410402114441421 |
6 | 412021455432355 |
7 | 32625513141503 |
oct | 4642160103657 |
9 | 1148350262708 |
10 | 331010312111 |
11 | 118420767816 |
12 | 5419a8256bb |
13 | 252a260180b |
14 | 12041820303 |
15 | 8924d547ab |
hex | 4d11c087af |
331010312111 has 4 divisors (see below), whose sum is σ = 337255789752. Its totient is φ = 324764834472.
The previous prime is 331010312089. The next prime is 331010312117. The reversal of 331010312111 is 111213010133.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111213010133 = 205817 ⋅540349.
It is a cyclic number.
It is not a de Polignac number, because 331010312111 - 218 = 331010049967 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 331010312111.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (331010312117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3122738741 + ... + 3122738846.
It is an arithmetic number, because the mean of its divisors is an integer number (84313947438).
Almost surely, 2331010312111 is an apocalyptic number.
331010312111 is a deficient number, since it is larger than the sum of its proper divisors (6245477641).
331010312111 is an equidigital number, since it uses as much as digits as its factorization.
331010312111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6245477640.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 331010312111 its reverse (111213010133), we get a palindrome (442223322244).
The spelling of 331010312111 in words is "three hundred thirty-one billion, ten million, three hundred twelve thousand, one hundred eleven".
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