331020211311323 has 2 divisors, whose sum is σ = 331020211311324. Its totient is φ = 331020211311322.

The previous prime is 331020211311289. The next prime is 331020211311331. The reversal of 331020211311323 is 323113112020133.

It is a strong prime.

It is an emirp because it is prime and its reverse (323113112020133) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-331020211311323 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 331020211311292 and 331020211311301.

It is not a weakly prime, because it can be changed into another prime (331020211301323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165510105655661 + 165510105655662.

It is an arithmetic number, because the mean of its divisors is an integer number (165510105655662).

Almost surely, 2^{331020211311323} is an apocalyptic number.

331020211311323 is a deficient number, since it is larger than the sum of its proper divisors (1).

331020211311323 is an equidigital number, since it uses as much as digits as its factorization.

331020211311323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 26.

Adding to 331020211311323 its reverse (323113112020133), we get a palindrome (654133323331456).

The spelling of 331020211311323 in words is "three hundred thirty-one trillion, twenty billion, two hundred eleven million, three hundred eleven thousand, three hundred twenty-three".