Base | Representation |
---|---|
bin | 1111000011011101000110… |
… | …10001001100001110111011 |
3 | 11100012201100022102120102121 |
4 | 13201232203101030032323 |
5 | 13314334044322034120 |
6 | 154223442553142111 |
7 | 6654455162310016 |
oct | 741564321141673 |
9 | 140181308376377 |
10 | 33104052143035 |
11 | a603393460975 |
12 | 38679540ba937 |
13 | 1561911128c53 |
14 | 82635d54c37d |
15 | 3c61a437c5aa |
hex | 1e1ba344c3bb |
33104052143035 has 32 divisors (see below), whose sum is σ = 42073456803840. Its totient is φ = 24961665982848.
The previous prime is 33104052143027. The next prime is 33104052143153. The reversal of 33104052143035 is 53034125040133.
It is a cyclic number.
It is not a de Polignac number, because 33104052143035 - 23 = 33104052143027 is a prime.
It is a super-2 number, since 2×331040521430352 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9910182 + ... + 12822628.
It is an arithmetic number, because the mean of its divisors is an integer number (1314795525120).
Almost surely, 233104052143035 is an apocalyptic number.
33104052143035 is a deficient number, since it is larger than the sum of its proper divisors (8969404660805).
33104052143035 is a wasteful number, since it uses less digits than its factorization.
33104052143035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2914347.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 33104052143035 its reverse (53034125040133), we get a palindrome (86138177183168).
The spelling of 33104052143035 in words is "thirty-three trillion, one hundred four billion, fifty-two million, one hundred forty-three thousand, thirty-five".
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