Base | Representation |
---|---|
bin | 110000001011110100010… |
… | …110101111100000110011 |
3 | 102201112211220220221100102 |
4 | 300023310112233200303 |
5 | 413222341422423103 |
6 | 11013053330543015 |
7 | 461141141116244 |
oct | 60136426574063 |
9 | 12645756827312 |
10 | 3311224420403 |
11 | 1067311953179 |
12 | 4558a2437a6b |
13 | 1b0329c10893 |
14 | b639aa46ccb |
15 | 5b1ec521e88 |
hex | 302f45af833 |
3311224420403 has 2 divisors, whose sum is σ = 3311224420404. Its totient is φ = 3311224420402.
The previous prime is 3311224420379. The next prime is 3311224420417. The reversal of 3311224420403 is 3040244221133.
3311224420403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3311224420403 - 212 = 3311224416307 is a prime.
It is not a weakly prime, because it can be changed into another prime (3311224420463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1655612210201 + 1655612210202.
It is an arithmetic number, because the mean of its divisors is an integer number (1655612210202).
Almost surely, 23311224420403 is an apocalyptic number.
3311224420403 is a deficient number, since it is larger than the sum of its proper divisors (1).
3311224420403 is an equidigital number, since it uses as much as digits as its factorization.
3311224420403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 3311224420403 its reverse (3040244221133), we get a palindrome (6351468641536).
The spelling of 3311224420403 in words is "three trillion, three hundred eleven billion, two hundred twenty-four million, four hundred twenty thousand, four hundred three".
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