Base | Representation |
---|---|
bin | 1001101000110001001… |
… | …11100111101011101011 |
3 | 1011122200201002022212001 |
4 | 10310120213213223223 |
5 | 20411121113134011 |
6 | 412041133031431 |
7 | 32631412330036 |
oct | 4643047475353 |
9 | 1148621068761 |
10 | 331125521131 |
11 | 11847a7a6a89 |
12 | 54211325577 |
13 | 252c043bb32 |
14 | 12052c5001d |
15 | 89300107c1 |
hex | 4d189e7aeb |
331125521131 has 2 divisors, whose sum is σ = 331125521132. Its totient is φ = 331125521130.
The previous prime is 331125521117. The next prime is 331125521137. The reversal of 331125521131 is 131125521133.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 331125521131 - 25 = 331125521099 is a prime.
It is a super-2 number, since 2×3311255211312 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 331125521131.
It is not a weakly prime, because it can be changed into another prime (331125521137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165562760565 + 165562760566.
It is an arithmetic number, because the mean of its divisors is an integer number (165562760566).
Almost surely, 2331125521131 is an apocalyptic number.
331125521131 is a deficient number, since it is larger than the sum of its proper divisors (1).
331125521131 is an equidigital number, since it uses as much as digits as its factorization.
331125521131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2700, while the sum is 28.
The spelling of 331125521131 in words is "three hundred thirty-one billion, one hundred twenty-five million, five hundred twenty-one thousand, one hundred thirty-one".
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