Base | Representation |
---|---|
bin | 100101101001010010111000… |
… | …1101000101001100011111001 |
3 | 1121102102210222201212102021001 |
4 | 1023102211301220221203321 |
5 | 321400222242011213423 |
6 | 3132131251552445001 |
7 | 126514265604334342 |
oct | 11322456150514371 |
9 | 1542383881772231 |
10 | 331131000101113 |
11 | 96565960a98343 |
12 | 3117b4a5b49761 |
13 | 1129c699c58614 |
14 | 5baab7c46b0c9 |
15 | 2843725913cad |
hex | 12d2971a298f9 |
331131000101113 has 2 divisors, whose sum is σ = 331131000101114. Its totient is φ = 331131000101112.
The previous prime is 331131000101093. The next prime is 331131000101123. The reversal of 331131000101113 is 311101000131133.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 224571564146944 + 106559435954169 = 14985712^2 + 10322763^2 .
It is a cyclic number.
It is not a de Polignac number, because 331131000101113 - 233 = 331122410166521 is a prime.
It is not a weakly prime, because it can be changed into another prime (331131000101123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165565500050556 + 165565500050557.
It is an arithmetic number, because the mean of its divisors is an integer number (165565500050557).
Almost surely, 2331131000101113 is an apocalyptic number.
It is an amenable number.
331131000101113 is a deficient number, since it is larger than the sum of its proper divisors (1).
331131000101113 is an equidigital number, since it uses as much as digits as its factorization.
331131000101113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 19.
Adding to 331131000101113 its reverse (311101000131133), we get a palindrome (642232000232246).
The spelling of 331131000101113 in words is "three hundred thirty-one trillion, one hundred thirty-one billion, one hundred one thousand, one hundred thirteen".
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