Base | Representation |
---|---|
bin | 1100010101011110… |
… | …1010000001111001 |
3 | 22112202211010111212 |
4 | 3011113222001321 |
5 | 23240144004032 |
6 | 1304324532505 |
7 | 145025460545 |
oct | 30527520171 |
9 | 8482733455 |
10 | 3311313017 |
11 | 144a171531 |
12 | 784b51135 |
13 | 40a04371c |
14 | 235ac2a25 |
15 | 145a89bb2 |
hex | c55ea079 |
3311313017 has 2 divisors, whose sum is σ = 3311313018. Its totient is φ = 3311313016.
The previous prime is 3311312941. The next prime is 3311313029. The reversal of 3311313017 is 7103131133.
3311313017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3115760761 + 195552256 = 55819^2 + 13984^2 .
It is a cyclic number.
It is not a de Polignac number, because 3311313017 - 216 = 3311247481 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3311312983 and 3311313001.
It is not a weakly prime, because it can be changed into another prime (3311313617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1655656508 + 1655656509.
It is an arithmetic number, because the mean of its divisors is an integer number (1655656509).
Almost surely, 23311313017 is an apocalyptic number.
It is an amenable number.
3311313017 is a deficient number, since it is larger than the sum of its proper divisors (1).
3311313017 is an equidigital number, since it uses as much as digits as its factorization.
3311313017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 567, while the sum is 23.
The square root of 3311313017 is about 57544.0093928117. The cubic root of 3311313017 is about 1490.5049137875.
The spelling of 3311313017 in words is "three billion, three hundred eleven million, three hundred thirteen thousand, seventeen".
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