Base | Representation |
---|---|
bin | 100101101001010011000010… |
… | …0001010110000010000000100 |
3 | 1121102102211210101221022021220 |
4 | 1023102212010022300100010 |
5 | 321400223411111000200 |
6 | 3132131342501040340 |
7 | 126514306401236343 |
oct | 11322460412602004 |
9 | 1542384711838256 |
10 | 331131311031300 |
11 | 9656600055783a |
12 | 3117b5720b60b0 |
13 | 1129c7194b2490 |
14 | 5baabab887b5a |
15 | 2843742d814a0 |
hex | 12d29842b0404 |
331131311031300 has 216 divisors, whose sum is σ = 1078581245382144. Its totient is φ = 77965365054720.
The previous prime is 331131311031259. The next prime is 331131311031331. The reversal of 331131311031300 is 3130113131133.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 78187812 + ... + 82314011.
It is an arithmetic number, because the mean of its divisors is an integer number (4993431691584).
Almost surely, 2331131311031300 is an apocalyptic number.
331131311031300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
331131311031300 is an abundant number, since it is smaller than the sum of its proper divisors (747449934350844).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
331131311031300 is a wasteful number, since it uses less digits than its factorization.
331131311031300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 160501899 (or 160501869 counting only the distinct ones).
The product of its (nonzero) digits is 729, while the sum is 24.
Adding to 331131311031300 its reverse (3130113131133), we get a palindrome (334261424162433).
The spelling of 331131311031300 in words is "three hundred thirty-one trillion, one hundred thirty-one billion, three hundred eleven million, thirty-one thousand, three hundred".
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