Base | Representation |
---|---|
bin | 100101101001010011100011… |
… | …0111000100011001000011010 |
3 | 1121102102221200102002200210202 |
4 | 1023102213012320203020122 |
5 | 321400233204131114232 |
6 | 3132132045523342202 |
7 | 126514346212161104 |
oct | 11322470670431032 |
9 | 1542387612080722 |
10 | 331132430332442 |
11 | 96566525355302 |
12 | 3117b824b21962 |
13 | 1129c86736044b |
14 | 5baac763ac574 |
15 | 28437ab27b162 |
hex | 12d29c6e2321a |
331132430332442 has 4 divisors (see below), whose sum is σ = 496698645498666. Its totient is φ = 165566215166220.
The previous prime is 331132430332423. The next prime is 331132430332453. The reversal of 331132430332442 is 244233034231133.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 192661645428121 + 138470784904321 = 13880261^2 + 11767361^2 .
It is a junction number, because it is equal to n+sod(n) for n = 331132430332396 and 331132430332405.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82783107583109 + ... + 82783107583112.
Almost surely, 2331132430332442 is an apocalyptic number.
331132430332442 is a deficient number, since it is larger than the sum of its proper divisors (165566215166224).
331132430332442 is a wasteful number, since it uses less digits than its factorization.
331132430332442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 165566215166223.
The product of its (nonzero) digits is 373248, while the sum is 38.
Adding to 331132430332442 its reverse (244233034231133), we get a palindrome (575365464563575).
The spelling of 331132430332442 in words is "three hundred thirty-one trillion, one hundred thirty-two billion, four hundred thirty million, three hundred thirty-two thousand, four hundred forty-two".
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