Base | Representation |
---|---|
bin | 100101101001010100010011… |
… | …0110110100011111011000100 |
3 | 1121102110002211121202211101022 |
4 | 1023102220212312203323010 |
5 | 321400300003322033012 |
6 | 3132132513401250312 |
7 | 126514434132552011 |
oct | 11322504666437304 |
9 | 1542402747684338 |
10 | 331134040424132 |
11 | 96567181199aa0 |
12 | 3117bbb4193998 |
13 | 1129ca62aba71a |
14 | 5baad8a16c708 |
15 | 28438527c0472 |
hex | 12d2a26da3ec4 |
331134040424132 has 24 divisors (see below), whose sum is σ = 632165541309120. Its totient is φ = 150515340766560.
The previous prime is 331134040424113. The next prime is 331134040424177. The reversal of 331134040424132 is 231424040431133.
It is a super-2 number, since 2×3311340404241322 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 331134040424092 and 331134040424101.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 61788938 + ... + 66933854.
It is an arithmetic number, because the mean of its divisors is an integer number (26340230887880).
Almost surely, 2331134040424132 is an apocalyptic number.
It is an amenable number.
331134040424132 is a deficient number, since it is larger than the sum of its proper divisors (301031500884988).
331134040424132 is a wasteful number, since it uses less digits than its factorization.
331134040424132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6607691 (or 6607689 counting only the distinct ones).
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 331134040424132 its reverse (231424040431133), we get a palindrome (562558080855265).
The spelling of 331134040424132 in words is "three hundred thirty-one trillion, one hundred thirty-four billion, forty million, four hundred twenty-four thousand, one hundred thirty-two".
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