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331143120 = 243357112181
BaseRepresentation
bin10011101111001…
…101011111010000
3212002002210222000
4103233031133100
51134233034440
652505314000
711130445560
oct2357153720
9762083860
10331143120
1115aa15800
1292a95900
13537b3199
1431d9cda0
151e111730
hex13bcd7d0

331143120 has 480 divisors, whose sum is σ = 1440741120. Its totient is φ = 68428800.

The previous prime is 331143097. The next prime is 331143133. The reversal of 331143120 is 21341133.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 331143093 and 331143102.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1829430 + ... + 1829610.

It is an arithmetic number, because the mean of its divisors is an integer number (3001544).

Almost surely, 2331143120 is an apocalyptic number.

331143120 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 331143120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (720370560).

331143120 is an abundant number, since it is smaller than the sum of its proper divisors (1109598000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

331143120 is a wasteful number, since it uses less digits than its factorization.

331143120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 232 (or 209 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

The square root of 331143120 is about 18197.3382669005. The cubic root of 331143120 is about 691.8393269700.

Adding to 331143120 its reverse (21341133), we get a palindrome (352484253).

It can be divided in two parts, 3311431 and 20, that added together give a triangular number (3311451 = T2573).

The spelling of 331143120 in words is "three hundred thirty-one million, one hundred forty-three thousand, one hundred twenty".