3311494843 has 2 divisors, whose sum is σ = 3311494844. Its totient is φ = 3311494842.

The previous prime is 3311494817. The next prime is 3311494873. The reversal of 3311494843 is 3484941133.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3311494843 - 2⁵ = 3311494811 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3311494796 and 3311494805.

It is not a weakly prime, because it can be changed into another prime (3311494873) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1655747421 + 1655747422.

It is an arithmetic number, because the mean of its divisors is an integer number (1655747422).

Almost surely, 2^3311494843 is an apocalyptic number.

3311494843 is a deficient number, since it is larger than the sum of its proper divisors (1).

3311494843 is an equidigital number, since it uses as much as digits as its factorization.

3311494843 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 124416, while the sum is 40.

The square root of 3311494843 is about 57545.5892575617. The cubic root of 3311494843 is about 1490.5321947668.

The spelling of 3311494843 in words is "three billion, three hundred eleven million, four hundred ninety-four thousand, eight hundred forty-three".