Base | Representation |
---|---|
bin | 110000001100100100100… |
… | …000101000101000010111 |
3 | 102201121221020010111021120 |
4 | 300030210200220220113 |
5 | 413231020233220043 |
6 | 11013305431015023 |
7 | 461200151133600 |
oct | 60144440505027 |
9 | 12647836114246 |
10 | 3312032320023 |
11 | 106769699a109 |
12 | 455a88b0a473 |
13 | 1b04283cb2ab |
14 | b643606ada7 |
15 | 5b248409983 |
hex | 30324828a17 |
3312032320023 has 24 divisors (see below), whose sum is σ = 5159659859712. Its totient is φ = 1884252477744.
The previous prime is 3312032319989. The next prime is 3312032320033. The reversal of 3312032320023 is 3200232302133.
It is not a de Polignac number, because 3312032320023 - 29 = 3312032319511 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3312032319975 and 3312032320002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3312032320033) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 49594015 + ... + 49660752.
It is an arithmetic number, because the mean of its divisors is an integer number (214985827488).
Almost surely, 23312032320023 is an apocalyptic number.
3312032320023 is a deficient number, since it is larger than the sum of its proper divisors (1847627539689).
3312032320023 is a wasteful number, since it uses less digits than its factorization.
3312032320023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 99255011 (or 99255004 counting only the distinct ones).
The product of its (nonzero) digits is 3888, while the sum is 24.
Adding to 3312032320023 its reverse (3200232302133), we get a palindrome (6512264622156).
The spelling of 3312032320023 in words is "three trillion, three hundred twelve billion, thirty-two million, three hundred twenty thousand, twenty-three".
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