33121013119 has 4 divisors (see below), whose sum is σ = 33331975144. Its totient is φ = 32910051096.

The previous prime is 33121013099. The next prime is 33121013137. The reversal of 33121013119 is 91131012133.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 33121013119 - 2¹³ = 33121004927 is a prime.

It is a super-2 number, since 2×33121013119² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 33121013093 and 33121013102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (33121014119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105480777 + ... + 105481090.

It is an arithmetic number, because the mean of its divisors is an integer number (8332993786).

Almost surely, 2^33121013119 is an apocalyptic number.

33121013119 is a deficient number, since it is larger than the sum of its proper divisors (210962025).

33121013119 is a wasteful number, since it uses less digits than its factorization.

33121013119 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 210962024.

The product of its (nonzero) digits is 486, while the sum is 25.

The spelling of 33121013119 in words is "thirty-three billion, one hundred twenty-one million, thirteen thousand, one hundred nineteen".