3312112132019 has 2 divisors, whose sum is σ = 3312112132020. Its totient is φ = 3312112132018.

The previous prime is 3312112132003. The next prime is 3312112132031. The reversal of 3312112132019 is 9102312112133.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3312112132019 - 2⁴ = 3312112132003 is a prime.

It is a super-2 number, since 2×3312112132019² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3312112131982 and 3312112132000.

It is not a weakly prime, because it can be changed into another prime (3312112132039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1656056066009 + 1656056066010.

It is an arithmetic number, because the mean of its divisors is an integer number (1656056066010).

Almost surely, 2^{3312112132019} is an apocalyptic number.

3312112132019 is a deficient number, since it is larger than the sum of its proper divisors (1).

3312112132019 is an equidigital number, since it uses as much as digits as its factorization.

3312112132019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 29.

The spelling of 3312112132019 in words is "three trillion, three hundred twelve billion, one hundred twelve million, one hundred thirty-two thousand, nineteen".