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3312212009993 is a prime number
BaseRepresentation
bin110000001100101111001…
…110000110010000001001
3102201122101202020200120122
4300030233032012100021
5413231402233304433
611013335330233025
7461204462361215
oct60145716062011
912648352220518
103312212009993
11106777936a917
12455b19125775
131b04566c4013
14b6451c83945
155b2590a1198
hex3032f386409

3312212009993 has 2 divisors, whose sum is σ = 3312212009994. Its totient is φ = 3312212009992.

The previous prime is 3312212009933. The next prime is 3312212010109. The reversal of 3312212009993 is 3999002122133.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2162273198089 + 1149938811904 = 1470467^2 + 1072352^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3312212009993 is a prime.

It is a super-3 number, since 3×33122120099933 (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (3312212009923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1656106004996 + 1656106004997.

It is an arithmetic number, because the mean of its divisors is an integer number (1656106004997).

Almost surely, 23312212009993 is an apocalyptic number.

It is an amenable number.

3312212009993 is a deficient number, since it is larger than the sum of its proper divisors (1).

3312212009993 is an equidigital number, since it uses as much as digits as its factorization.

3312212009993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 157464, while the sum is 44.

The spelling of 3312212009993 in words is "three trillion, three hundred twelve billion, two hundred twelve million, nine thousand, nine hundred ninety-three".