Base | Representation |
---|---|
bin | 1111000100000010100001… |
… | …10110110110110010010011 |
3 | 11100021122012120110010220201 |
4 | 13202001100312312302103 |
5 | 13320201221423003321 |
6 | 154241004414520031 |
7 | 6656066114225014 |
oct | 742012066666223 |
9 | 140248176403821 |
10 | 33124144344211 |
11 | a610963a35008 |
12 | 386b820b06017 |
13 | 156379394669b |
14 | 827307b9500b |
15 | 3c697d25c291 |
hex | 1e2050db6c93 |
33124144344211 has 2 divisors, whose sum is σ = 33124144344212. Its totient is φ = 33124144344210.
The previous prime is 33124144344167. The next prime is 33124144344251. The reversal of 33124144344211 is 11244344142133.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-33124144344211 is a prime.
It is a super-2 number, since 2×331241443442112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (33124144344251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16562072172105 + 16562072172106.
It is an arithmetic number, because the mean of its divisors is an integer number (16562072172106).
Almost surely, 233124144344211 is an apocalyptic number.
33124144344211 is a deficient number, since it is larger than the sum of its proper divisors (1).
33124144344211 is an equidigital number, since it uses as much as digits as its factorization.
33124144344211 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 110592, while the sum is 37.
Adding to 33124144344211 its reverse (11244344142133), we get a palindrome (44368488486344).
The spelling of 33124144344211 in words is "thirty-three trillion, one hundred twenty-four billion, one hundred forty-four million, three hundred forty-four thousand, two hundred eleven".
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