Base | Representation |
---|---|
bin | 11110110110011010… |
… | …101010101100100001 |
3 | 10011111112221021102011 |
4 | 132312122222230201 |
5 | 1020320023340014 |
6 | 23114552152521 |
7 | 2251605452605 |
oct | 366632525441 |
9 | 104445837364 |
10 | 33125215009 |
11 | 13059358357 |
12 | 6505698741 |
13 | 317b9ab153 |
14 | 1863527505 |
15 | cdd1a37c4 |
hex | 7b66aab21 |
33125215009 has 2 divisors, whose sum is σ = 33125215010. Its totient is φ = 33125215008.
The previous prime is 33125214989. The next prime is 33125215129. The reversal of 33125215009 is 90051252133.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24219140625 + 8906074384 = 155625^2 + 94372^2 .
It is an emirp because it is prime and its reverse (90051252133) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 33125215009 - 25 = 33125214977 is a prime.
It is not a weakly prime, because it can be changed into another prime (33125215609) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16562607504 + 16562607505.
It is an arithmetic number, because the mean of its divisors is an integer number (16562607505).
Almost surely, 233125215009 is an apocalyptic number.
It is an amenable number.
33125215009 is a deficient number, since it is larger than the sum of its proper divisors (1).
33125215009 is an equidigital number, since it uses as much as digits as its factorization.
33125215009 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8100, while the sum is 31.
The spelling of 33125215009 in words is "thirty-three billion, one hundred twenty-five million, two hundred fifteen thousand, nine".
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