Search a number
-
+
3312593131 is a prime number
BaseRepresentation
bin1100010101110010…
…0010100011101011
322112212020011111111
43011130202203223
523241010440011
61304412211151
7145042401631
oct30534424353
98485204444
103312593131
11144a966281
12785469ab7
1340a3a12a3
14235d37351
15145c3e121
hexc57228eb

3312593131 has 2 divisors, whose sum is σ = 3312593132. Its totient is φ = 3312593130.

The previous prime is 3312593113. The next prime is 3312593159. The reversal of 3312593131 is 1313952133.

3312593131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (3312593113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3312593131 - 25 = 3312593099 is a prime.

It is a super-2 number, since 2×33125931312 = 21946546503096766322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3312593093 and 3312593102.

It is not a weakly prime, because it can be changed into another prime (3312593731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1656296565 + 1656296566.

It is an arithmetic number, because the mean of its divisors is an integer number (1656296566).

Almost surely, 23312593131 is an apocalyptic number.

3312593131 is a deficient number, since it is larger than the sum of its proper divisors (1).

3312593131 is an equidigital number, since it uses as much as digits as its factorization.

3312593131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7290, while the sum is 31.

The square root of 3312593131 is about 57555.1312308468. The cubic root of 3312593131 is about 1490.6969594985.

The spelling of 3312593131 in words is "three billion, three hundred twelve million, five hundred ninety-three thousand, one hundred thirty-one".