Base | Representation |
---|---|
bin | 11110110110101100… |
… | …111111110101110110 |
3 | 10011111212222101220201 |
4 | 132312230333311312 |
5 | 1020322241121324 |
6 | 23115243151114 |
7 | 2251664345134 |
oct | 366654776566 |
9 | 104455871821 |
10 | 33130020214 |
11 | 1306103a5a5 |
12 | 650721549a |
13 | 317c9a1375 |
14 | 1864018754 |
15 | cdd802444 |
hex | 7b6b3fd76 |
33130020214 has 8 divisors (see below), whose sum is σ = 49773788208. Its totient is φ = 16538757480.
The previous prime is 33130020169. The next prime is 33130020233. The reversal of 33130020214 is 41202003133.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 33130020191 and 33130020200.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13124737 + ... + 13127260.
It is an arithmetic number, because the mean of its divisors is an integer number (6221723526).
Almost surely, 233130020214 is an apocalyptic number.
33130020214 is a deficient number, since it is larger than the sum of its proper divisors (16643767994).
33130020214 is a wasteful number, since it uses less digits than its factorization.
33130020214 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26252630.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 33130020214 its reverse (41202003133), we get a palindrome (74332023347).
The spelling of 33130020214 in words is "thirty-three billion, one hundred thirty million, twenty thousand, two hundred fourteen".
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