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33140404134 = 2321841133563
BaseRepresentation
bin11110110111010100…
…100110111110100110
310011112121111221222100
4132313110212332212
51020332420413014
623120253512530
72252151534015
oct366724467646
9104477457870
1033140404134
1113066992152
12650a7a2746
133181b988b6
14186555ca7c
15cde6a4009
hex7b7526fa6

33140404134 has 12 divisors (see below), whose sum is σ = 71804208996. Its totient is φ = 11046801372.

The previous prime is 33140404127. The next prime is 33140404249. The reversal of 33140404134 is 43140404133.

It is a junction number, because it is equal to n+sod(n) for n = 33140404098 and 33140404107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 920566764 + ... + 920566799.

It is an arithmetic number, because the mean of its divisors is an integer number (5983684083).

Almost surely, 233140404134 is an apocalyptic number.

33140404134 is an abundant number, since it is smaller than the sum of its proper divisors (38663804862).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

33140404134 is a wasteful number, since it uses less digits than its factorization.

33140404134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1841133571 (or 1841133568 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 33140404134 its reverse (43140404133), we get a palindrome (76280808267).

Subtracting 33140404134 from its reverse (43140404133), we obtain a palindrome (9999999999).

The spelling of 33140404134 in words is "thirty-three billion, one hundred forty million, four hundred four thousand, one hundred thirty-four".

Divisors: 1 2 3 6 9 18 1841133563 3682267126 5523400689 11046801378 16570202067 33140404134