Base | Representation |
---|---|
bin | 110000001110011100010… |
… | …011011000101111101001 |
3 | 102201211010021220112221112 |
4 | 300032130103120233221 |
5 | 413244124240104001 |
6 | 11014241103520105 |
7 | 461301024113414 |
oct | 60163423305751 |
9 | 12654107815845 |
10 | 3314042113001 |
11 | 1068528415344 |
12 | 456349bb9035 |
13 | 1b06888c3bc9 |
14 | b6586d54b7b |
15 | 5b314aa3cbb |
hex | 3039c4d8be9 |
3314042113001 has 2 divisors, whose sum is σ = 3314042113002. Its totient is φ = 3314042113000.
The previous prime is 3314042112991. The next prime is 3314042113051. The reversal of 3314042113001 is 1003112404133.
3314042113001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1962226632025 + 1351815480976 = 1400795^2 + 1162676^2 .
It is a cyclic number.
It is not a de Polignac number, because 3314042113001 - 210 = 3314042111977 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (3314042113051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657021056500 + 1657021056501.
It is an arithmetic number, because the mean of its divisors is an integer number (1657021056501).
Almost surely, 23314042113001 is an apocalyptic number.
It is an amenable number.
3314042113001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3314042113001 is an equidigital number, since it uses as much as digits as its factorization.
3314042113001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 3314042113001 its reverse (1003112404133), we get a palindrome (4317154517134).
The spelling of 3314042113001 in words is "three trillion, three hundred fourteen billion, forty-two million, one hundred thirteen thousand, one".
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