Base | Representation |
---|---|
bin | 1111000100100000111101… |
… | …10000100110111010011001 |
3 | 11100100012101021212011112011 |
4 | 13202100132300212322121 |
5 | 13320433202312332323 |
6 | 154252310020145521 |
7 | 6660215036461504 |
oct | 742203660467231 |
9 | 140305337764464 |
10 | 33140483714713 |
11 | a6178890a49a1 |
12 | 3872a20b382a1 |
13 | 1565198b0385b |
14 | 828017c2813b |
15 | 3c70d793c20d |
hex | 1e241ec26e99 |
33140483714713 has 2 divisors, whose sum is σ = 33140483714714. Its totient is φ = 33140483714712.
The previous prime is 33140483714699. The next prime is 33140483714743. The reversal of 33140483714713 is 31741738404133.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24501193217424 + 8639290497289 = 4949868^2 + 2939267^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-33140483714713 is a prime.
It is not a weakly prime, because it can be changed into another prime (33140483714743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16570241857356 + 16570241857357.
It is an arithmetic number, because the mean of its divisors is an integer number (16570241857357).
Almost surely, 233140483714713 is an apocalyptic number.
It is an amenable number.
33140483714713 is a deficient number, since it is larger than the sum of its proper divisors (1).
33140483714713 is an equidigital number, since it uses as much as digits as its factorization.
33140483714713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2032128, while the sum is 49.
The spelling of 33140483714713 in words is "thirty-three trillion, one hundred forty billion, four hundred eighty-three million, seven hundred fourteen thousand, seven hundred thirteen".
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