Base | Representation |
---|---|
bin | 1001101001010011011… |
… | …00111101100010100011 |
3 | 1011200102200101202212101 |
4 | 10310221230331202203 |
5 | 20412213001242201 |
6 | 412125412111231 |
7 | 32641462442155 |
oct | 4645154754243 |
9 | 1150380352771 |
10 | 331412134051 |
11 | 118607567569 |
12 | 54291305517 |
13 | 2533793048b |
14 | 1207cd3aad5 |
15 | 894a277d01 |
hex | 4d29b3d8a3 |
331412134051 has 2 divisors, whose sum is σ = 331412134052. Its totient is φ = 331412134050.
The previous prime is 331412134013. The next prime is 331412134057. The reversal of 331412134051 is 150431214133.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 331412134051 - 213 = 331412125859 is a prime.
It is not a weakly prime, because it can be changed into another prime (331412134057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165706067025 + 165706067026.
It is an arithmetic number, because the mean of its divisors is an integer number (165706067026).
Almost surely, 2331412134051 is an apocalyptic number.
331412134051 is a deficient number, since it is larger than the sum of its proper divisors (1).
331412134051 is an equidigital number, since it uses as much as digits as its factorization.
331412134051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 331412134051 its reverse (150431214133), we get a palindrome (481843348184).
The spelling of 331412134051 in words is "three hundred thirty-one billion, four hundred twelve million, one hundred thirty-four thousand, fifty-one".
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