3314220433 has 4 divisors (see below), whose sum is σ = 3376752948. Its totient is φ = 3251687920.

The previous prime is 3314220419. The next prime is 3314220439. The reversal of 3314220433 is 3340224133.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3340224133 = 43 ⋅77679631.

It can be written as a sum of positive squares in 2 ways, for example, as 1230115329 + 2084105104 = 35073^2 + 45652^2 .

It is a cyclic number.

It is not a de Polignac number, because 3314220433 - 2²¹ = 3312123281 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3314220398 and 3314220407.

It is not an unprimeable number, because it can be changed into a prime (3314220439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31266178 + ... + 31266283.

It is an arithmetic number, because the mean of its divisors is an integer number (844188237).

Almost surely, 2^3314220433 is an apocalyptic number.

It is an amenable number.

3314220433 is a deficient number, since it is larger than the sum of its proper divisors (62532515).

3314220433 is an equidigital number, since it uses as much as digits as its factorization.

3314220433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62532514.

The product of its (nonzero) digits is 5184, while the sum is 25.

The square root of 3314220433 is about 57569.2663927551. The cubic root of 3314220433 is about 1490.9410197589.

Adding to 3314220433 its reverse (3340224133), we get a palindrome (6654444566).

The spelling of 3314220433 in words is "three billion, three hundred fourteen million, two hundred twenty thousand, four hundred thirty-three".