3314341129993 has 2 divisors, whose sum is σ = 3314341129994. Its totient is φ = 3314341129992.

The previous prime is 3314341129933. The next prime is 3314341130027. The reversal of 3314341129993 is 3999211434133.

3314341129993 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3314340404089 + 725904 = 1820533^2 + 852^2 .

It is an emirp because it is prime and its reverse (3999211434133) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3314341129993 - 2¹⁷ = 3314340998921 is a prime.

It is a super-2 number, since 2×3314341129993² (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3314341129993.

It is not a weakly prime, because it can be changed into another prime (3314341129933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657170564996 + 1657170564997.

It is an arithmetic number, because the mean of its divisors is an integer number (1657170564997).

Almost surely, 2^{3314341129993} is an apocalyptic number.

It is an amenable number.

3314341129993 is a deficient number, since it is larger than the sum of its proper divisors (1).

3314341129993 is an equidigital number, since it uses as much as digits as its factorization.

3314341129993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1889568, while the sum is 52.

The spelling of 3314341129993 in words is "three trillion, three hundred fourteen billion, three hundred forty-one million, one hundred twenty-nine thousand, nine hundred ninety-three".