Base | Representation |
---|---|
bin | 11110110111100110… |
… | …100001100001000001 |
3 | 10011112221100112222101 |
4 | 132313212201201001 |
5 | 1020340121202403 |
6 | 23120542310401 |
7 | 2252236463431 |
oct | 366746414101 |
9 | 104487315871 |
10 | 33145100353 |
11 | 130695aa522 |
12 | 6510288401 |
13 | 3182b51321 |
14 | 18660222c1 |
15 | cdecd071d |
hex | 7b79a1841 |
33145100353 has 2 divisors, whose sum is σ = 33145100354. Its totient is φ = 33145100352.
The previous prime is 33145100309. The next prime is 33145100357. The reversal of 33145100353 is 35300154133.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31929043969 + 1216056384 = 178687^2 + 34872^2 .
It is an emirp because it is prime and its reverse (35300154133) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 33145100353 - 217 = 33144969281 is a prime.
It is not a weakly prime, because it can be changed into another prime (33145100357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16572550176 + 16572550177.
It is an arithmetic number, because the mean of its divisors is an integer number (16572550177).
Almost surely, 233145100353 is an apocalyptic number.
It is an amenable number.
33145100353 is a deficient number, since it is larger than the sum of its proper divisors (1).
33145100353 is an equidigital number, since it uses as much as digits as its factorization.
33145100353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8100, while the sum is 28.
Adding to 33145100353 its reverse (35300154133), we get a palindrome (68445254486).
The spelling of 33145100353 in words is "thirty-three billion, one hundred forty-five million, one hundred thousand, three hundred fifty-three".
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