Base | Representation |
---|---|
bin | 100101101011101001110100… |
… | …0110001110111101011010101 |
3 | 1121110120210121022120012221001 |
4 | 1023113103220301313223111 |
5 | 321421030042104213013 |
6 | 3132540214124223301 |
7 | 126546561621252643 |
oct | 11327235061675325 |
9 | 1543523538505831 |
10 | 331455121554133 |
11 | 96680367111285 |
12 | 3121228169ab31 |
13 | 112c4112298945 |
14 | 5bbc728dc2193 |
15 | 284bd95aa4ddd |
hex | 12d74e8c77ad5 |
331455121554133 has 4 divisors (see below), whose sum is σ = 331455626740480. Its totient is φ = 331454616367788.
The previous prime is 331455121554091. The next prime is 331455121554173.
It is a happy number.
331455121554133 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-331455121554133 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (331455121554173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 251607735 + ... + 252921652.
It is an arithmetic number, because the mean of its divisors is an integer number (82863906685120).
Almost surely, 2331455121554133 is an apocalyptic number.
It is an amenable number.
331455121554133 is a deficient number, since it is larger than the sum of its proper divisors (505186347).
331455121554133 is an equidigital number, since it uses as much as digits as its factorization.
331455121554133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 505186346.
The product of its digits is 1620000, while the sum is 46.
The spelling of 331455121554133 in words is "three hundred thirty-one trillion, four hundred fifty-five billion, one hundred twenty-one million, five hundred fifty-four thousand, one hundred thirty-three".
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