3320004012433 has 4 divisors (see below), whose sum is σ = 3354230858020. Its totient is φ = 3285777166848.

The previous prime is 3320004012427. The next prime is 3320004012439. The reversal of 3320004012433 is 3342104000233.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (3320004012427) and next prime (3320004012439).

It can be written as a sum of positive squares in 2 ways, for example, as 977047240849 + 2342956771584 = 988457^2 + 1530672^2 .

It is a cyclic number.

It is not a de Polignac number, because 3320004012433 - 2¹³ = 3320004004241 is a prime.

It is a super-2 number, since 2×3320004012433² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3320004012398 and 3320004012407.

It is not an unprimeable number, because it can be changed into a prime (3320004012439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17113422648 + ... + 17113422841.

It is an arithmetic number, because the mean of its divisors is an integer number (838557714505).

Almost surely, 2^{3320004012433} is an apocalyptic number.

It is an amenable number.

3320004012433 is a deficient number, since it is larger than the sum of its proper divisors (34226845587).

3320004012433 is an equidigital number, since it uses as much as digits as its factorization.

3320004012433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34226845586.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 3320004012433 its reverse (3342104000233), we get a palindrome (6662108012666).

The spelling of 3320004012433 in words is "three trillion, three hundred twenty billion, four million, twelve thousand, four hundred thirty-three".