Base | Representation |
---|---|
bin | 110000010100000000001… |
… | …010010001110011000111 |
3 | 102202101112101002021110100 |
4 | 300110000022101303013 |
5 | 413343341134223101 |
6 | 11021105340055143 |
7 | 461602000616256 |
oct | 60240012216307 |
9 | 12671471067410 |
10 | 3320012414151 |
11 | 1070011500a24 |
12 | 4575355344b3 |
13 | 1b10ca791a94 |
14 | b6991c3279d |
15 | 5b563cc1e86 |
hex | 30500291cc7 |
3320012414151 has 24 divisors (see below), whose sum is σ = 4801131078224. Its totient is φ = 2210777452800.
The previous prime is 3320012414123. The next prime is 3320012414167. The reversal of 3320012414151 is 1514142100233.
3320012414151 is a `hidden beast` number, since 3 + 3 + 2 + 0 + 0 + 1 + 241 + 415 + 1 = 666.
It is not a de Polignac number, because 3320012414151 - 211 = 3320012412103 is a prime.
It is a super-2 number, since 2×33200124141512 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3320012412151) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 49124655 + ... + 49192191.
Almost surely, 23320012414151 is an apocalyptic number.
3320012414151 is a deficient number, since it is larger than the sum of its proper divisors (1481118664073).
3320012414151 is a wasteful number, since it uses less digits than its factorization.
3320012414151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73791 (or 73788 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 3320012414151 its reverse (1514142100233), we get a palindrome (4834154514384).
The spelling of 3320012414151 in words is "three trillion, three hundred twenty billion, twelve million, four hundred fourteen thousand, one hundred fifty-one".
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