33200311000130 has 48 divisors (see below), whose sum is σ = 61257900049920. Its totient is φ = 12955327390080.

The previous prime is 33200311000127. The next prime is 33200311000187. The reversal of 33200311000130 is 3100011300233.

It is a super-3 number, since 3×33200311000130³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 33200311000099 and 33200311000108.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 278095391 + ... + 278214749.

It is an arithmetic number, because the mean of its divisors is an integer number (1276206251040).

Almost surely, 2^{33200311000130} is an apocalyptic number.

33200311000130 is a deficient number, since it is larger than the sum of its proper divisors (28057589049790).

33200311000130 is a wasteful number, since it uses less digits than its factorization.

33200311000130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 135995 (or 135954 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 33200311000130 its reverse (3100011300233), we get a palindrome (36300322300363).

The spelling of 33200311000130 in words is "thirty-three trillion, two hundred billion, three hundred eleven million, one hundred thirty", and thus it is an aban number.