Base | Representation |
---|---|
bin | 1001101010011011000… |
… | …01100110001000000011 |
3 | 1011201222120021202021022 |
4 | 10311031201212020003 |
5 | 20414430330244324 |
6 | 412305201420055 |
7 | 32662411035455 |
oct | 4651541461003 |
9 | 1151876252238 |
10 | 332013134339 |
11 | 118895838a17 |
12 | 5441a63a62b |
13 | 254022b9453 |
14 | 120d8aa42d5 |
15 | 8982de205e |
hex | 4d4d866203 |
332013134339 has 2 divisors, whose sum is σ = 332013134340. Its totient is φ = 332013134338.
The previous prime is 332013134311. The next prime is 332013134353. The reversal of 332013134339 is 933431310233.
It is a strong prime.
It is an emirp because it is prime and its reverse (933431310233) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 332013134339 - 212 = 332013130243 is a prime.
It is a super-2 number, since 2×3320131343392 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 332013134299 and 332013134308.
It is not a weakly prime, because it can be changed into another prime (332013634339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166006567169 + 166006567170.
It is an arithmetic number, because the mean of its divisors is an integer number (166006567170).
Almost surely, 2332013134339 is an apocalyptic number.
332013134339 is a deficient number, since it is larger than the sum of its proper divisors (1).
332013134339 is an equidigital number, since it uses as much as digits as its factorization.
332013134339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488, while the sum is 35.
The spelling of 332013134339 in words is "three hundred thirty-two billion, thirteen million, one hundred thirty-four thousand, three hundred thirty-nine".
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