Base | Representation |
---|---|
bin | 100101101111101101110010… |
… | …1010110011100100000000000 |
3 | 1121112120011122101100200200000 |
4 | 1023133123211112130200000 |
5 | 322004201430401004020 |
6 | 3134044504350400000 |
7 | 126635114543014110 |
oct | 11337334526344000 |
9 | 1545504571320600 |
10 | 332013409781760 |
11 | 96876107282923 |
12 | 312a250b200000 |
13 | 11334965334b25 |
14 | 5bdb76b5cb040 |
15 | 285b66da0e090 |
hex | 12df6e559c800 |
332013409781760 has 2304 divisors, whose sum is σ = 1427238601850880. Its totient is φ = 72426116874240.
The previous prime is 332013409781719. The next prime is 332013409781777. The reversal of 332013409781760 is 67187904310233.
332013409781760 is a `hidden beast` number, since 3 + 3 + 201 + 340 + 97 + 8 + 1 + 7 + 6 + 0 = 666.
It is a tau number, because it is divible by the number of its divisors (2304).
It is a super-2 number, since 2×3320134097817602 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (54).
It is a junction number, because it is equal to n+sod(n) for n = 332013409781697 and 332013409781706.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 39417472909 + ... + 39417481331.
It is an arithmetic number, because the mean of its divisors is an integer number (619461198720).
Almost surely, 2332013409781760 is an apocalyptic number.
332013409781760 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 332013409781760, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (713619300925440).
332013409781760 is an abundant number, since it is smaller than the sum of its proper divisors (1095225192069120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
332013409781760 is an equidigital number, since it uses as much as digits as its factorization.
332013409781760 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8576 (or 8544 counting only the distinct ones).
The product of its (nonzero) digits is 4572288, while the sum is 54.
The spelling of 332013409781760 in words is "three hundred thirty-two trillion, thirteen billion, four hundred nine million, seven hundred eighty-one thousand, seven hundred sixty".
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