Base | Representation |
---|---|
bin | 100101101111101110100110… |
… | …0011111001111101110111011 |
3 | 1121112120100002222100002200201 |
4 | 1023133131030133033232323 |
5 | 322004214001334021021 |
6 | 3134045352202143031 |
7 | 126635205453565144 |
oct | 11337351437175673 |
9 | 1545510088302621 |
10 | 332015140142011 |
11 | 96876914aa2117 |
12 | 312a29127b1a77 |
13 | 11334b7c981331 |
14 | 5bdb893336acb |
15 | 285b7208ad591 |
hex | 12df74c7cfbbb |
332015140142011 has 2 divisors, whose sum is σ = 332015140142012. Its totient is φ = 332015140142010.
The previous prime is 332015140141991. The next prime is 332015140142051. The reversal of 332015140142011 is 110241041510233.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 332015140142011 - 245 = 296830768053179 is a prime.
It is a super-2 number, since 2×3320151401420112 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (332015140142051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166007570071005 + 166007570071006.
It is an arithmetic number, because the mean of its divisors is an integer number (166007570071006).
Almost surely, 2332015140142011 is an apocalyptic number.
332015140142011 is a deficient number, since it is larger than the sum of its proper divisors (1).
332015140142011 is an equidigital number, since it uses as much as digits as its factorization.
332015140142011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 332015140142011 its reverse (110241041510233), we get a palindrome (442256181652244).
The spelling of 332015140142011 in words is "three hundred thirty-two trillion, fifteen billion, one hundred forty million, one hundred forty-two thousand, eleven".
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