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332015140142011 is a prime number
BaseRepresentation
bin100101101111101110100110…
…0011111001111101110111011
31121112120100002222100002200201
41023133131030133033232323
5322004214001334021021
63134045352202143031
7126635205453565144
oct11337351437175673
91545510088302621
10332015140142011
1196876914aa2117
12312a29127b1a77
1311334b7c981331
145bdb893336acb
15285b7208ad591
hex12df74c7cfbbb

332015140142011 has 2 divisors, whose sum is σ = 332015140142012. Its totient is φ = 332015140142010.

The previous prime is 332015140141991. The next prime is 332015140142051. The reversal of 332015140142011 is 110241041510233.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 332015140142011 - 245 = 296830768053179 is a prime.

It is a super-2 number, since 2×3320151401420112 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (332015140142051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166007570071005 + 166007570071006.

It is an arithmetic number, because the mean of its divisors is an integer number (166007570071006).

Almost surely, 2332015140142011 is an apocalyptic number.

332015140142011 is a deficient number, since it is larger than the sum of its proper divisors (1).

332015140142011 is an equidigital number, since it uses as much as digits as its factorization.

332015140142011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 332015140142011 its reverse (110241041510233), we get a palindrome (442256181652244).

The spelling of 332015140142011 in words is "three hundred thirty-two trillion, fifteen billion, one hundred forty million, one hundred forty-two thousand, eleven".