332120231404034 has 4 divisors (see below), whose sum is σ = 498180347106054. Its totient is φ = 166060115702016.

The previous prime is 332120231404001. The next prime is 332120231404067. The reversal of 332120231404034 is 430404132021233.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (332120231404001) and next prime (332120231404067).

It can be written as a sum of positive squares in only one way, i.e., 226875140640625 + 105245090763409 = 15062375^2 + 10258903^2 .

It is a super-3 number, since 3×332120231404034³ (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83030057851007 + ... + 83030057851010.

Almost surely, 2^{332120231404034} is an apocalyptic number.

332120231404034 is a deficient number, since it is larger than the sum of its proper divisors (166060115702020).

332120231404034 is a wasteful number, since it uses less digits than its factorization.

332120231404034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 166060115702019.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 332120231404034 its reverse (430404132021233), we get a palindrome (762524363425267).

The spelling of 332120231404034 in words is "three hundred thirty-two trillion, one hundred twenty billion, two hundred thirty-one million, four hundred four thousand, thirty-four".