Base | Representation |
---|---|
bin | 110000010101001101000… |
… | …010000010100011000001 |
3 | 102202111212020212010001212 |
4 | 300111031002002203001 |
5 | 413404011314201121 |
6 | 11021441330335505 |
7 | 461645651021633 |
oct | 60251502024301 |
9 | 12674766763055 |
10 | 3321302100161 |
11 | 10706134a4131 |
12 | 45783542a595 |
13 | 1b1274a282b6 |
14 | b6a7522aa53 |
15 | 5b5dc12625b |
hex | 3054d0828c1 |
3321302100161 has 2 divisors, whose sum is σ = 3321302100162. Its totient is φ = 3321302100160.
The previous prime is 3321302100097. The next prime is 3321302100169. The reversal of 3321302100161 is 1610012031233.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2212450979761 + 1108851120400 = 1487431^2 + 1053020^2 .
It is a cyclic number.
It is not a de Polignac number, because 3321302100161 - 26 = 3321302100097 is a prime.
It is a super-3 number, since 3×33213021001613 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (3321302100169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1660651050080 + 1660651050081.
It is an arithmetic number, because the mean of its divisors is an integer number (1660651050081).
Almost surely, 23321302100161 is an apocalyptic number.
It is an amenable number.
3321302100161 is a deficient number, since it is larger than the sum of its proper divisors (1).
3321302100161 is an equidigital number, since it uses as much as digits as its factorization.
3321302100161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 3321302100161 its reverse (1610012031233), we get a palindrome (4931314131394).
The spelling of 3321302100161 in words is "three trillion, three hundred twenty-one billion, three hundred two million, one hundred thousand, one hundred sixty-one".
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