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33214130311342 = 216607065155671
BaseRepresentation
bin1111000110101010001000…
…11100000101000010101110
311100121020110211220220120011
413203111010130011002232
513323140014324430332
6154350205534243434
76665433053304301
oct743250434050256
9140536424826504
1033214130311342
11a646040740a92
12388515505657a
13156c104894596
1482b802c7cb38
153c8e98265e47
hex1e35447050ae

33214130311342 has 4 divisors (see below), whose sum is σ = 49821195467016. Its totient is φ = 16607065155670.

The previous prime is 33214130311339. The next prime is 33214130311421. The reversal of 33214130311342 is 24311303141233.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×332141303113423 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8303532577834 + ... + 8303532577837.

It is an arithmetic number, because the mean of its divisors is an integer number (12455298866754).

Almost surely, 233214130311342 is an apocalyptic number.

33214130311342 is a deficient number, since it is larger than the sum of its proper divisors (16607065155674).

33214130311342 is a wasteful number, since it uses less digits than its factorization.

33214130311342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16607065155673.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 33214130311342 its reverse (24311303141233), we get a palindrome (57525433452575).

The spelling of 33214130311342 in words is "thirty-three trillion, two hundred fourteen billion, one hundred thirty million, three hundred eleven thousand, three hundred forty-two".

Divisors: 1 2 16607065155671 33214130311342