Base | Representation |
---|---|
bin | 1111000110101010001000… |
… | …11100000101000010101110 |
3 | 11100121020110211220220120011 |
4 | 13203111010130011002232 |
5 | 13323140014324430332 |
6 | 154350205534243434 |
7 | 6665433053304301 |
oct | 743250434050256 |
9 | 140536424826504 |
10 | 33214130311342 |
11 | a646040740a92 |
12 | 388515505657a |
13 | 156c104894596 |
14 | 82b802c7cb38 |
15 | 3c8e98265e47 |
hex | 1e35447050ae |
33214130311342 has 4 divisors (see below), whose sum is σ = 49821195467016. Its totient is φ = 16607065155670.
The previous prime is 33214130311339. The next prime is 33214130311421. The reversal of 33214130311342 is 24311303141233.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×332141303113423 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8303532577834 + ... + 8303532577837.
It is an arithmetic number, because the mean of its divisors is an integer number (12455298866754).
Almost surely, 233214130311342 is an apocalyptic number.
33214130311342 is a deficient number, since it is larger than the sum of its proper divisors (16607065155674).
33214130311342 is a wasteful number, since it uses less digits than its factorization.
33214130311342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16607065155673.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 33214130311342 its reverse (24311303141233), we get a palindrome (57525433452575).
The spelling of 33214130311342 in words is "thirty-three trillion, two hundred fourteen billion, one hundred thirty million, three hundred eleven thousand, three hundred forty-two".
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