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332161444161233 is a prime number
BaseRepresentation
bin100101110000110010101110…
…0111000110010011011010001
31121120002022202011011100002022
41023201211130320302123101
5322014113114201124413
63134240505541101225
7126651605143332221
oct11341453470623321
91546068664140068
10332161444161233
11969229718861a5
12313071436b7815
13113458c75b63cb
145c049b1cb2081
152860434c6c608
hex12e195ce326d1

332161444161233 has 2 divisors, whose sum is σ = 332161444161234. Its totient is φ = 332161444161232.

The previous prime is 332161444161191. The next prime is 332161444161361.

332161444161233 is nontrivially palindromic in base 10.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 284422423469584 + 47739020691649 = 16864828^2 + 6909343^2 .

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 332161444161233 - 216 = 332161444095697 is a prime.

It is a super-3 number, since 3×3321614441612333 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (332161444121233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166080722080616 + 166080722080617.

It is an arithmetic number, because the mean of its divisors is an integer number (166080722080617).

Almost surely, 2332161444161233 is an apocalyptic number.

It is an amenable number.

332161444161233 is a deficient number, since it is larger than the sum of its proper divisors (1).

332161444161233 is an equidigital number, since it uses as much as digits as its factorization.

332161444161233 is an evil number, because the sum of its binary digits is even.

The product of its digits is 746496, while the sum is 44.

The spelling of 332161444161233 in words is "three hundred thirty-two trillion, one hundred sixty-one billion, four hundred forty-four million, one hundred sixty-one thousand, two hundred thirty-three".