Base | Representation |
---|---|
bin | 110000010101110111010… |
… | …111011100010111100011 |
3 | 102202120200202022202012022 |
4 | 300111313113130113203 |
5 | 413411440130312034 |
6 | 11022040021452055 |
7 | 462002364050612 |
oct | 60256727342743 |
9 | 12676622282168 |
10 | 3322012354019 |
11 | 1070948407397 |
12 | 4579b327102b |
13 | 1b1358c17958 |
14 | b6b016b3879 |
15 | 5b62e671b2e |
hex | 305775dc5e3 |
3322012354019 has 2 divisors, whose sum is σ = 3322012354020. Its totient is φ = 3322012354018.
The previous prime is 3322012353971. The next prime is 3322012354027. The reversal of 3322012354019 is 9104532102233.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3322012354019 - 220 = 3322011305443 is a prime.
It is a super-2 number, since 2×33220123540192 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3322012354019.
It is not a weakly prime, because it can be changed into another prime (3322012354079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1661006177009 + 1661006177010.
It is an arithmetic number, because the mean of its divisors is an integer number (1661006177010).
Almost surely, 23322012354019 is an apocalyptic number.
3322012354019 is a deficient number, since it is larger than the sum of its proper divisors (1).
3322012354019 is an equidigital number, since it uses as much as digits as its factorization.
3322012354019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 35.
The spelling of 3322012354019 in words is "three trillion, three hundred twenty-two billion, twelve million, three hundred fifty-four thousand, nineteen".
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