Base | Representation |
---|---|
bin | 1111000111001000000101… |
… | …10111101001111001111011 |
3 | 11100122202222110220110212011 |
4 | 13203210002313221321323 |
5 | 13323420432242110042 |
6 | 154401425304230351 |
7 | 6666542404334035 |
oct | 743440267517173 |
9 | 140582873813764 |
10 | 33230210113147 |
11 | a651942332093 |
12 | 38882a216b3b7 |
13 | 157079803b8c8 |
14 | 82c4ca664c55 |
15 | 3c95d9c71a17 |
hex | 1e3902de9e7b |
33230210113147 has 2 divisors, whose sum is σ = 33230210113148. Its totient is φ = 33230210113146.
The previous prime is 33230210113091. The next prime is 33230210113159. The reversal of 33230210113147 is 74131101203233.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 33230210113147 - 219 = 33230209588859 is a prime.
It is a super-2 number, since 2×332302101131472 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (33230210113447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16615105056573 + 16615105056574.
It is an arithmetic number, because the mean of its divisors is an integer number (16615105056574).
Almost surely, 233230210113147 is an apocalyptic number.
33230210113147 is a deficient number, since it is larger than the sum of its proper divisors (1).
33230210113147 is an equidigital number, since it uses as much as digits as its factorization.
33230210113147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 31.
The spelling of 33230210113147 in words is "thirty-three trillion, two hundred thirty billion, two hundred ten million, one hundred thirteen thousand, one hundred forty-seven".
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