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33231010212131 is a prime number
BaseRepresentation
bin1111000111001001100101…
…00011110010100100100011
311100122212001020102201022212
413203210302203302210203
513323424102103242011
6154402040525152335
76666601261142114
oct743446243624443
9140585036381285
1033231010212131
11a652212a30316
1238884860bb6ab
131570894a27864
1482c564a1820b
153c963511808b
hex1e39328f2923

33231010212131 has 2 divisors, whose sum is σ = 33231010212132. Its totient is φ = 33231010212130.

The previous prime is 33231010212109. The next prime is 33231010212161. The reversal of 33231010212131 is 13121201013233.

It is a weak prime.

It is an emirp because it is prime and its reverse (13121201013233) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33231010212131 - 222 = 33231006017827 is a prime.

It is a super-2 number, since 2×332310102121312 (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 33231010212097 and 33231010212106.

It is not a weakly prime, because it can be changed into another prime (33231010212161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16615505106065 + 16615505106066.

It is an arithmetic number, because the mean of its divisors is an integer number (16615505106066).

Almost surely, 233231010212131 is an apocalyptic number.

33231010212131 is a deficient number, since it is larger than the sum of its proper divisors (1).

33231010212131 is an equidigital number, since it uses as much as digits as its factorization.

33231010212131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 33231010212131 its reverse (13121201013233), we get a palindrome (46352211225364).

The spelling of 33231010212131 in words is "thirty-three trillion, two hundred thirty-one billion, ten million, two hundred twelve thousand, one hundred thirty-one".