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33242143404433 is a prime number
BaseRepresentation
bin1111000111011110010100…
…01001100011000110010001
311100200220210010111111001111
413203233022021203012101
513324114402202420213
6154411121352133321
710000444205542525
oct743571211430621
9140626703444044
1033242143404433
11a656a06370497
12388a672697241
13157194a417a02
1482ccdd479d85
153c9a87716a3d
hex1e3bca263191

33242143404433 has 2 divisors, whose sum is σ = 33242143404434. Its totient is φ = 33242143404432.

The previous prime is 33242143404419. The next prime is 33242143404451. The reversal of 33242143404433 is 33440434124233.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33083283765249 + 158859639184 = 5751807^2 + 398572^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-33242143404433 is a prime.

It is a super-2 number, since 2×332421434044332 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (33242143404413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16621071702216 + 16621071702217.

It is an arithmetic number, because the mean of its divisors is an integer number (16621071702217).

Almost surely, 233242143404433 is an apocalyptic number.

It is an amenable number.

33242143404433 is a deficient number, since it is larger than the sum of its proper divisors (1).

33242143404433 is an equidigital number, since it uses as much as digits as its factorization.

33242143404433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 995328, while the sum is 40.

Adding to 33242143404433 its reverse (33440434124233), we get a palindrome (66682577528666).

The spelling of 33242143404433 in words is "thirty-three trillion, two hundred forty-two billion, one hundred forty-three million, four hundred four thousand, four hundred thirty-three".