Base | Representation |
---|---|
bin | 110000011000000001100… |
… | …110000011111111001001 |
3 | 102202210200101002122000020 |
4 | 300120001212003333021 |
5 | 413431212322121441 |
6 | 11023102103531053 |
7 | 462114014012454 |
oct | 60300146037711 |
9 | 12683611078006 |
10 | 3324331442121 |
11 | 1071928485628 |
12 | 45833ba59a89 |
13 | 1b1638514131 |
14 | b6c816b049b |
15 | 5b718063e66 |
hex | 30601983fc9 |
3324331442121 has 64 divisors (see below), whose sum is σ = 4658403778560. Its totient is φ = 2106412888320.
The previous prime is 3324331442099. The next prime is 3324331442149. The reversal of 3324331442121 is 1212441334233.
It is not a de Polignac number, because 3324331442121 - 210 = 3324331441097 is a prime.
It is a super-2 number, since 2×33243314421212 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (3324331442921) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1630372420 + ... + 1630374458.
It is an arithmetic number, because the mean of its divisors is an integer number (72787559040).
Almost surely, 23324331442121 is an apocalyptic number.
It is an amenable number.
3324331442121 is a deficient number, since it is larger than the sum of its proper divisors (1334072336439).
3324331442121 is a wasteful number, since it uses less digits than its factorization.
3324331442121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3206.
The product of its digits is 41472, while the sum is 33.
Adding to 3324331442121 its reverse (1212441334233), we get a palindrome (4536772776354).
The spelling of 3324331442121 in words is "three trillion, three hundred twenty-four billion, three hundred thirty-one million, four hundred forty-two thousand, one hundred twenty-one".
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