33244004344121 has 2 divisors, whose sum is σ = 33244004344122. Its totient is φ = 33244004344120.

The previous prime is 33244004344081. The next prime is 33244004344141. The reversal of 33244004344121 is 12144340044233.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21181754388496 + 12062249955625 = 4602364^2 + 3473075^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-33244004344121 is a prime.

It is a super-3 number, since 3×33244004344121³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (33244004344141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16622002172060 + 16622002172061.

It is an arithmetic number, because the mean of its divisors is an integer number (16622002172061).

Almost surely, 2^{33244004344121} is an apocalyptic number.

It is an amenable number.

33244004344121 is a deficient number, since it is larger than the sum of its proper divisors (1).

33244004344121 is an equidigital number, since it uses as much as digits as its factorization.

33244004344121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 33244004344121 its reverse (12144340044233), we get a palindrome (45388344388354).

The spelling of 33244004344121 in words is "thirty-three trillion, two hundred forty-four billion, four million, three hundred forty-four thousand, one hundred twenty-one".