Base | Representation |
---|---|
bin | 10011110110001… |
… | …011010010011001 |
3 | 212012112120202101 |
4 | 103312023102121 |
5 | 1140220002423 |
6 | 53012403401 |
7 | 11152122301 |
oct | 2366132231 |
9 | 765476671 |
10 | 332969113 |
11 | 160a52694 |
12 | 93616561 |
13 | 53ca2359 |
14 | 32316601 |
15 | 1e3727ad |
hex | 13d8b499 |
332969113 has 2 divisors, whose sum is σ = 332969114. Its totient is φ = 332969112.
The previous prime is 332969107. The next prime is 332969141. The reversal of 332969113 is 311969233.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 308634624 + 24334489 = 17568^2 + 4933^2 .
It is an emirp because it is prime and its reverse (311969233) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 332969113 - 225 = 299414681 is a prime.
It is a super-2 number, since 2×3329691132 = 221736860424013538, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (332969173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166484556 + 166484557.
It is an arithmetic number, because the mean of its divisors is an integer number (166484557).
Almost surely, 2332969113 is an apocalyptic number.
It is an amenable number.
332969113 is a deficient number, since it is larger than the sum of its proper divisors (1).
332969113 is an equidigital number, since it uses as much as digits as its factorization.
332969113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 26244, while the sum is 37.
The square root of 332969113 is about 18247.4412726826. The cubic root of 332969113 is about 693.1086460414.
The spelling of 332969113 in words is "three hundred thirty-two million, nine hundred sixty-nine thousand, one hundred thirteen".
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