Base | Representation |
---|---|
bin | 110000011101010100001… |
… | …100000101000110010001 |
3 | 102210100100021021022110102 |
4 | 300131110030011012101 |
5 | 414024331044412103 |
6 | 11025441512142145 |
7 | 462404542612214 |
oct | 60352414050621 |
9 | 12710307238412 |
10 | 3330012107153 |
11 | 1074283026316 |
12 | 459466397955 |
13 | 1b20323a25a4 |
14 | b725dd1577b |
15 | 5b94bb1de88 |
hex | 30754305191 |
3330012107153 has 2 divisors, whose sum is σ = 3330012107154. Its totient is φ = 3330012107152.
The previous prime is 3330012107099. The next prime is 3330012107269. The reversal of 3330012107153 is 3517012100333.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2683512488449 + 646499618704 = 1638143^2 + 804052^2 .
It is a cyclic number.
It is not a de Polignac number, because 3330012107153 - 222 = 3330007912849 is a prime.
It is a super-2 number, since 2×33300121071532 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3330012107053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665006053576 + 1665006053577.
It is an arithmetic number, because the mean of its divisors is an integer number (1665006053577).
Almost surely, 23330012107153 is an apocalyptic number.
It is an amenable number.
3330012107153 is a deficient number, since it is larger than the sum of its proper divisors (1).
3330012107153 is an equidigital number, since it uses as much as digits as its factorization.
3330012107153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5670, while the sum is 29.
Adding to 3330012107153 its reverse (3517012100333), we get a palindrome (6847024207486).
The spelling of 3330012107153 in words is "three trillion, three hundred thirty billion, twelve million, one hundred seven thousand, one hundred fifty-three".
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