3330041414113 has 2 divisors, whose sum is σ = 3330041414114. Its totient is φ = 3330041414112.

The previous prime is 3330041414047. The next prime is 3330041414123. The reversal of 3330041414113 is 3114141400333.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2460201661009 + 869839753104 = 1568503^2 + 932652^2 .

It is a cyclic number.

It is not a de Polignac number, because 3330041414113 - 2¹³ = 3330041405921 is a prime.

It is a super-2 number, since 2×3330041414113² (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3330041414123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665020707056 + 1665020707057.

It is an arithmetic number, because the mean of its divisors is an integer number (1665020707057).

Almost surely, 2^{3330041414113} is an apocalyptic number.

It is an amenable number.

3330041414113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3330041414113 is an equidigital number, since it uses as much as digits as its factorization.

3330041414113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 3330041414113 its reverse (3114141400333), we get a palindrome (6444182814446).

The spelling of 3330041414113 in words is "three trillion, three hundred thirty billion, forty-one million, four hundred fourteen thousand, one hundred thirteen".